x^2+3x-50=20

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Solution for x^2+3x-50=20 equation:


Simplifying
x2 + 3x + -50 = 20

Reorder the terms:
-50 + 3x + x2 = 20

Solving
-50 + 3x + x2 = 20

Solving for variable 'x'.

Reorder the terms:
-50 + -20 + 3x + x2 = 20 + -20

Combine like terms: -50 + -20 = -70
-70 + 3x + x2 = 20 + -20

Combine like terms: 20 + -20 = 0
-70 + 3x + x2 = 0

Factor a trinomial.
(-10 + -1x)(7 + -1x) = 0

Subproblem 1

Set the factor '(-10 + -1x)' equal to zero and attempt to solve: Simplifying -10 + -1x = 0 Solving -10 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + -1x = 0 + 10 Combine like terms: -10 + 10 = 0 0 + -1x = 0 + 10 -1x = 0 + 10 Combine like terms: 0 + 10 = 10 -1x = 10 Divide each side by '-1'. x = -10 Simplifying x = -10

Subproblem 2

Set the factor '(7 + -1x)' equal to zero and attempt to solve: Simplifying 7 + -1x = 0 Solving 7 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1x = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1x = 0 + -7 -1x = 0 + -7 Combine like terms: 0 + -7 = -7 -1x = -7 Divide each side by '-1'. x = 7 Simplifying x = 7

Solution

x = {-10, 7}

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